Великденски Яйца

Програмиране с Python

Курс във Факултета по Математика и Информатика към СУ

Решение на Астрологични забави от Дарко Алексов

Обратно към всички решения

Към профила на Дарко Алексов

Резултати

  • 10 точки от тестове
  • 1 отнета точка
  • 9 точки общо
  • 6 успешни тест(а)
  • 0 неуспешни тест(а)

Код

western_signs = ('aries', 'taurus', 'gemini', 'cancer', 'leo', 'virgo',
'libra', 'scorpio', 'sagittarius', 'capricorn',
'aquarius', 'pisces')
chinese_signs = ('rat', 'ox', 'tiger', 'rabbit', 'dragon', 'snake', 'horse',
'sheep', 'monkey', 'rooster', 'dog', 'pig')
def interpret_western_sign(day, month):
if (month == 3 and day < 21) or (month == 2 and 18 < day < 30):
return western_signs[11]
elif (month == 4 and day < 21) or (month == 3 and 20 < day < 32):
return western_signs[0]
elif (month == 5 and day < 21) or (month == 4 and 20 < day < 31):
return western_signs[1]
elif (month == 6 and day < 21) or (month == 5 and 20 < day < 32):
return western_signs[2]
elif (month == 7 and day < 23) or (month == 6 and 20 < day < 31):
return western_signs[3]
elif (month == 8 and day < 23) or (month == 7 and 22 < day < 32):
return western_signs[4]
elif (month == 9 and day < 23) or (month == 8 and 22 < day < 32):
return western_signs[5]
elif (month == 10 and day < 23) or (month == 9 and 22 < day < 31):
return western_signs[6]
elif (month == 11 and day < 22) or (month == 10 and 22 < day < 32):
return western_signs[7]
elif (month == 12 and day < 22) or (month == 11 and 21 < day < 31):
return western_signs[8]
elif (month == 1 and day < 21) or (month == 12 and 21 < day < 32):
return western_signs[9]
elif (month == 2 and day < 19) or (month == 1 and 20 < day < 32):
return western_signs[10]
def interpret_chinese_sign(year):
if year % 12 == 4:
return chinese_signs[0]
elif year % 12 == 5:
return chinese_signs[1]
elif year % 12 == 6:
return chinese_signs[2]
elif year % 12 == 7:
return chinese_signs[3]
elif year % 12 == 8:
return chinese_signs[4]
elif year % 12 == 9:
return chinese_signs[5]
elif year % 12 == 10:
return chinese_signs[6]
elif year % 12 == 11:
return chinese_signs[7]
elif year % 12 == 0:
return chinese_signs[8]
elif year % 12 == 1:
return chinese_signs[9]
elif year % 12 == 2:
return chinese_signs[10]
elif year % 12 == 3:
return chinese_signs[11]
def interpret_both_signs(day, month, year):
return (interpret_western_sign(int(day), int(month)),
interpret_chinese_sign(int(year)))

Лог от изпълнението

......
----------------------------------------------------------------------
Ran 6 tests in 0.006s

OK

История (1 версия и 1 коментар)

Дарко обнови решението на 11.03.2015 15:23 (преди над 9 години)

+western_signs = ('aries', 'taurus', 'gemini', 'cancer', 'leo', 'virgo',
+ 'libra', 'scorpio', 'sagittarius', 'capricorn',
+ 'aquarius', 'pisces')
+chinese_signs = ('rat', 'ox', 'tiger', 'rabbit', 'dragon', 'snake', 'horse',
+ 'sheep', 'monkey', 'rooster', 'dog', 'pig')
+
+
+def interpret_western_sign(day, month):
+ if (month == 3 and day < 21) or (month == 2 and 18 < day < 30):
+ return western_signs[11]
+ elif (month == 4 and day < 21) or (month == 3 and 20 < day < 32):
+ return western_signs[0]
+ elif (month == 5 and day < 21) or (month == 4 and 20 < day < 31):
+ return western_signs[1]
+ elif (month == 6 and day < 21) or (month == 5 and 20 < day < 32):
+ return western_signs[2]
+ elif (month == 7 and day < 23) or (month == 6 and 20 < day < 31):
+ return western_signs[3]
+ elif (month == 8 and day < 23) or (month == 7 and 22 < day < 32):
+ return western_signs[4]
+ elif (month == 9 and day < 23) or (month == 8 and 22 < day < 32):
+ return western_signs[5]
+ elif (month == 10 and day < 23) or (month == 9 and 22 < day < 31):
+ return western_signs[6]
+ elif (month == 11 and day < 22) or (month == 10 and 22 < day < 32):
+ return western_signs[7]
+ elif (month == 12 and day < 22) or (month == 11 and 21 < day < 31):
+ return western_signs[8]
+ elif (month == 1 and day < 21) or (month == 12 and 21 < day < 32):
+ return western_signs[9]
+ elif (month == 2 and day < 19) or (month == 1 and 20 < day < 32):
+ return western_signs[10]
+
+
+def interpret_chinese_sign(year):
+ if year % 12 == 4:
+ return chinese_signs[0]
+ elif year % 12 == 5:
+ return chinese_signs[1]
+ elif year % 12 == 6:
+ return chinese_signs[2]
+ elif year % 12 == 7:
+ return chinese_signs[3]
+ elif year % 12 == 8:
+ return chinese_signs[4]
+ elif year % 12 == 9:
+ return chinese_signs[5]
+ elif year % 12 == 10:
+ return chinese_signs[6]
+ elif year % 12 == 11:
+ return chinese_signs[7]
+ elif year % 12 == 0:
+ return chinese_signs[8]
+ elif year % 12 == 1:
+ return chinese_signs[9]
+ elif year % 12 == 2:
+ return chinese_signs[10]
+ elif year % 12 == 3:
+ return chinese_signs[11]
+
+
+def interpret_both_signs(day, month, year):
+ return (interpret_western_sign(int(day), int(month)),
+ interpret_chinese_sign(int(year)))
  • с тези if-ове ако имаше 102 зодии щеше да се побъркаш
  • времето, оставащо до крайния срок е малко, но имам някакво убеждение, че може да се досетиш как да премахнеш if-овете поне от функцията interpret_chinese_sign
  • глобалните променливи се пишат в SCREAM_SNAKE_CASE
  • няма нужда от това конвертиране към int() в interpret_both_signs (и даже ще ти се събере на един ред)