Цветан обнови решението на 21.03.2015 21:17 (преди около 9 години)
+def extract_type(text, result_type):
+ result_string = ""
+ for element in text:
+ if type(element[0]) is result_type:
+ result_string += str(element[0]) * element[1]
+ return result_string
+
+
+def reversed_dict(elements):
+ keys = []
+ new_items = []
+ items = list(elements.items())
+ for item in items:
+ if not item[1] in keys:
+ keys.append(item[1])
+ new_items.append((item[1], item[0]))
+ return dict(new_items)
+
+
+def flatten_dict_help(elements, flatten_elements, previous_key=''):
+ for key, value in elements.items():
+ if previous_key:
+ new_key = previous_key + '.' + key
+ else:
+ new_key = key
+ if type(value) is not dict:
+ flatten_elements.append((new_key, value))
+ else:
+ flatten_dict_help(value, flatten_elements, new_key)
+ return dict(flatten_elements)
+
+
+def flatten_dict(elements):
+ flatten_elements = []
+ return flatten_dict_help(elements, flatten_elements)
+
+
+def unflatten_dict(elements):
+ unflatten_elements = dict()
+ for key, value in elements.items():
+ current_elements = unflatten_elements
+ if len(key) > 1:
+ keys = key.split('.')
+ while len(keys) > 1:
+ if keys[0] not in current_elements:
+ current_elements[keys[0]] = dict()
+ current_elements = current_elements[keys[0]]
+ keys.pop(0)
+ current_elements[keys[0]] = value
+ else:
+ current_elements[key] = value
+ return unflatten_elements
+
+
+def counter_of_element(element, elements):
+ return len([x for x in elements if x == element])
+
+
+def reps(elements):
+ return tuple([element for element in elements
+ if counter_of_element(element, elements) > 1])